(x)=x^2-10x-96

Solution for (x)=x^2-10x-96 equation:

(x)=x^2-10x-96

We move all terms to the left:

(x)-(x^2-10x-96)=0

We get rid of parentheses

-x^2+x+10x+96=0

We add all the numbers together, and all the variables

-1x^2+11x+96=0

a = -1; b = 11; c = +96;
Δ = b2-4ac
Δ = 112-4·(-1)·96
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{505}}{2*-1}=\frac{-11-\sqrt{505}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{505}}{2*-1}=\frac{-11+\sqrt{505}}{-2}
$